Saturday, May 17, 2014

Here is what I mean about the number line and Plancks curve

If you take my spectral chart, before the particles are in place, you can consider that the number line with just the whole numbers and no notches in between.  Then you cram a bunch of vacuum energy up the thing, it hits the Higgs are wave 107, and bounces back.  When it bounces back it adjusts whole and fractional notches so the whole spectral chart now fits a Planck's curve.

So, Higgs is the sample rate of light, its nominal precision, the difference between (1/2+sqrt(5)/2)^107 and (3/2)^127; is the precision of light. That sets Planck, and light.  Every things else in the universe, from the atom to the quasar is determined by that match up. If there is any precision left, then we have neighboring universes and we share vacuum bubbles.

So, we whould not be surprised if:

2^N - 1 = Higgs/(Higgs Precision) , because that is the maximum entropy encoding (thermal equilibrium) and any set of separable items counted on a ruler with measurement error spread evenly. The ratio on the right is the curvature of the ruler, and should apply to anything at maximum entropy from protons to vacuum bubbles to universes. it is the fundamental definition of counting. N is finite, the natural log is finite.

Wait, isn't there always an optimum spot on the prime number line that sets Higgs and precision to a constant? Dunno, ask the mathematician who is destined for the Nobel. But I think the Zeta function says that may be correct. The multiplicative identity and the next two number define the densest region of groups, and set the Higgs to 107 always? Maybe.



Here is Max himself. I love these photos when the physicist looks like a young maniac.





Is there a better theory of counting?
Sure, if you can prove that there is an energy loss function that always results in more precision, until infinity. That may be true, and that would make free space independent of the vacuum.

The theory I propose is only limited by a finite set of bubbles. If bubbles were infinitely available, the universes would just keep building countable sets in recursive fashion.If the number of bubbles is finite, then we cycle thru even/odd vacuum noise quants.

No comments: