Tuesday, June 17, 2014

Degrees of freedom in the quarks

This is color, the bandwidth between the quarks and gluons essentially. I see three degrees of freedom, I am not including the anti quarks. Then baryon number and angular momentum is fixed for all, but charge has three degrees of freedom, including the electoron. Then ISO spin, but that only appears in up and down quarks, the ones that make protons and neutrons. Nor to the up and down have charm and strangeness. Hmm...

They say the mass is relativistic, but what they mean is that the gluon is a tub of Nulls that 1 to 3 waves short of a packed Null, so no  unit circle. It makes waves with a few bits of high frequency motion. The various masses, then, must be composed of separate three bits, each with one degrees of freedom. Right? The unit circle is the first Lagrange, no?  Especially since I do not think we trade quark pairs until we break something and have to renormalize. So, for each normal configuration, all the bits are centered about the one mass bit.

So the gluons likely set the bandwidth of the combined orbitals to something like:

Phi^17 is the largest quant and they can be decomposed into units of 1/Phi^17.  Guaranteed never to make a unit circle. They would be somewhat smaller than or equal to the smallest unit of null as 1/Phi^17.

In base 2, the proton has about 109 units of variation devoted to mass, and it varies little so they are likely the most significant of our 16 total bits. They are something near the top four bits at Lagrange 1 and define the four unit circles. The electron seems to be about 1/17 of the rest masses of the quarks.

So what do we make of the unit of charge in wave motion? It is one value that can appear in three locations, all rotations about a radial from the center of the unit circle. But the relative angle of that radial is determined by motion of the unit circle. The entire system is four gear systems, comprising 16 bits/ 4 (each, I think),  designed to move the four unit circles, all centered within the bandwidth of the gluon center.

What causes motion?
Deformation of the unit spheres by the action of the fractional bits, the 1/2^16, (I think) within the unit spheres, the inverse of the hyperbolic wave motion outside. These fraction changes of phase variation inside the unit spheres are actually designed to restore curvature. They will have the same degrees of freedom.

I am not sure about much of this, like are there four yardsticks with one Unit one each, or one yardstick with four unit ones? We only have about 16-19 total, so consider the electron. One for mass at Lagrange 1, one for spin at Lagrange 2 and one for charge at Lagrange 3. Including degrees of freedom, (which are bits, really, it has 6 bits. Higher orders of Lagrange are more minimum redundant, you get more bit action per degree than the lower orders.

Other clues:
Treated as four independent rulers, we have to identical quarks, which therefore must be positioned mostly orthogonal to each other. Second, all three spheres have the same degress of freedom, and must have the same number of equivalents bits (entropy).  And they are all equally subject to bandwidth restrictions, both in limits an separation of bits. So I am at least at 20 bits, but some of that is compaction because of Lagrange optimization.  It is four, including all bases, then we fit into the 156 bit system and still fill the bandwidth.

What about motion?
That seems to be another amount of entropy, no doesn't it? I have not figured that one out.

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