Saturday, August 30, 2014

Spectrum, sphere packing and quarks

We have quarks because there are few configurations for packing three spheres in the center of the proton.   Its a volume to surface area problem.The edge of the proton is right where the Compton spectrum almost nearly matches the Null numbers.  So the packing would leave mostly trapped light and kinetic energy would have to be narrow band and very high frequency. The density gradient so high that the spectrum would have a very long tail to the edge, all the way to the electron band where electrons would form. So, the system was stuck with the electron and needed charge to hold them together.  But a phase shift in the dense nulls in the center needs band stops for kinetic energy. Kinetic energy eats up bandwidth if you have this huge unite sphere.  So break them in two and have opposite spin? Then there is unbalanced charge because we still need to fill the electron spectral gap.

This works. The Y axis is the Compton spectral match, it is optimum at zero. The Efimov solution, it allows a net positive charge and room for high frequency motion of the unit spheres.  Unit spheres have wider or narrower hyperbolic angles when we phase shift. 

I think that right, I will double check.  In this case the two quarks with negative positive charge got the narrow angle and the quark with  positive negative charge the wide, making the isosceles triangle. The two symmetric quarks use the symmetric cubic root and thus operate with a shift in delta N between them, their quantum numbers must have an integer shift. The unit spheres move inside and along the arms, I think. If this is right, then the electron has the narrowest wide angle, I need to think this through a bit.

So am I saying that fibonacci numbers have size?

I dunno, I may have myself in a pickle, still thinking. But most likely both bubble sizes exist in streams. They will sort themselves out.

Having a very good Compton spectral match.  This is the peak of the proton, very well matched.  The quarks try to remove phase imbalance by kinetic energy but get close to equilibrium and kinetic spectrum is gone. The  positive quarks move along the circle to the negative quark, acquiring charge.  With only 1/3 charge, they quickly cease moving. And they always keep one quant apart along the hyperbolic arms. So they see saw. The quark with the negative positive charge is pulling in positive negative from the electron. I doubt these unit spheres can make more than two exchanges at a time, and mostly use one hyperbolic arm to point skyward, outside the bag. Inside the spheres they run a log network, a finite graph with the 1/F, and the ins and outs have to closely match.

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