Saturday, March 28, 2015

The Lepton has to be a composite particle

Let's do some back of the envelope on this.

The ratio of the proton to electron is 1836.  We have three quarks, so they independently, manage one third each or 606 each. Now that number is roughly 2^9, but with hyperbolics (and Feynman) they run bidirectional flows, so make that 4^5.  Ok, this makes since since 4^phi = 3*pi, so we can see the quarks baking three pies.  And the 4^5 can be broken inot three groups, each a 1/phi^5 times the previous,  and the exponent matches the number of spectral modes for the quark; we have a way to make quarks work.

Great, things fit.  Now what about the electron itself? It has about 2^50 bubbles of the vacuum inside.  (After all, Avogadro is the iron law of spheres).  So, those bubbles have to be managed as grouped particles, as there is no way to fit all the bubbls onto on tanh curve and still make the connections. Ergo, the lepton is a composite particle, case closed.
 
What kind of particles? Well make them with the second Lagrange number, and they don't bake the good pi, but so they are a bit redundant in their Feynman transitions; they spin to make up for it. So you get something like 4^5 bubbles per small thing, and they group by fives, each crammed badly onto Tanh and using the redundant Lagrange.  That gets to 2^50 bubbles of vacuum and we are home free.  Or we have the second and third Lagrange in their, and the electron is always spinning and on the move, but it holds integrity.  The quarks can work with that, and refine the accuracy of pi.

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