I always assumed the peak of
tanh'', taken positive, was at
log(phi^(3/2)), I never checked. Then one day I did
tanh'''=0, low and behold, what is the hyperbolic condition at that point?
3-2=1, I kid you not.
Tanh = sqrt(2/3), a familiar ratio. This is just set combinatorics, and hyperbolics do sets really nicely.
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