When quarks and gluons do the curl

In my model of the proton, with this mass of free null in the center, I have the gluons trying to curl those nulls with the quark they have, add them up.  So we end up with six degrees of freedom, three qluons doing the curl and three packed nulls.  Work out the angles and you can see we get the sphere carved up by two angles for each of three pairs, and the thing will balance like a perfect gyro. 

The GUT energy

The grand unification energy , or the GUT scale, is the energy level above which, it is believed, the electromagnetic force, weak force, and strong force become equal in strength and unify to one force governed by a simple Lie group. 

 What they mean is: Is there some large k,j such that:

(mass quant)^j/(light quant)^2k > 1/2 j,k integer

and

(mass quant)^m/(light quant)^2n < 1/2 for m < j and n < k

They want only one null quant and one wave quant; they want only one Shannon separated potential barrier. I presume they want this to happen somewhere above the proton quant levels. When that happens, Shannon tells me a mass looks like 2^S, S being the digit in some twos binary number as Nyquist.  I assume that also matches the Compton frequency, so mass/frequency  = 1.
So mass/Freq^2 = 2^(-S). And:
Momentum = 2^2S | energy = 2^3S | amount or probability = 2^S.
Temperature is 2^(S+1), Nyquist, or twice per item .
Time is probability, 2^S, the numbers of bits needed for the thing to happen.


I looked, up to the precision of my R Code, didn't see one. There problem is they need to find a perfectly flat vacuum to perform the experiment, good luck!

The idea of the desert was motivated by the observation of approximate, order of magnitude, gauge coupling unification at the GUT scale. 

They do this because they do not believe in the null bubble. I am accused of making simple groups, making use of the zero. They want me to stand on a knifes edge and get closer to 'divide by zero' then has ever been done.

If the world were symmetric enough, they could find a better Taylor series expansion for the vacuum that achieved precision with fewer multiplies, that is, take a tiny step closer to zero. If they find that point, then space is more continuous then it was before, and they can move the objects around with finer granularity. That is called, keep a continuous Lagrange point, like the L1 points in gravity we talked about.

I call it, "The proton making better use of the number 11", before the Phd students steal the number.

Can the bubbles improve the proton over time?

That is sort of a philosophical problem, because if we assume there is bubble and nothing else, then the bubbles have to be cubes, no empty spaces. I have not worked that problem, but it seems germane.  If the bubbles have to think like spheres but pack like cubes, then we are beyond anything I have worked out.
What I am wondering is why free nulls end up at the center of action.  We never see packed nulls except to the periphery, the most compact form, it seems is free nulls mixed with wave motion. But the null must be the middle size, I would think.

The prime answer is the proton is stuck because there are only three bubble types.

Hmmm.

Is the the gluon mystery solved?

All of these wave numbers near the top are up against the wall, literally, and mixed modes between them are stuck, they have reached the bandwidth if light.

So you have six or eight wave numbers that can pack either of two mass quants, and they try. But they are up against the sample rate of light, and each one almost get a packed null bot is interfered with by one of two other. So we end up with three gluons at a time chasing Null base plus (3/2)^7 9 nulls in the center, making the perfect spherical wave.  All of these gluons are 7 multiples, and always there is just not enough nulls in the center to make a packed set with their quarks. That wave action is three waves doing the mutual curl.

So, those tricky bubbles

Having bumped against the density of space, what do they do? The create every nook and cranny to pack nulls and wave motion, thus generating every know prime number up to 13. So, the solution is to think like a phase, every prime number, or some isolated pair of them, allows some wave motion up to 7*13, and pack as much nulls as 3*3*3*2*2. They are maximum entropy nutcases.

Those free nulls in the middle, and about half the mass count up to 108, are all likely barely measurable by any momentum operator.  Wave motion makes those thing appear still.

More gluon clues

This property of the strong force is called color confinement, and it prevents the free "emission" of strong force: instead, in practice, jets of massive particles are observed.

Simply, the gluons wipe out three mass slots and the quarks takes the 2/3 charge phase imbalance.  That make the bandwidth (three wave numbers) very high for a gluons and when they make travelling wave, they make a sharply pointed ellipsoid. They mix with nearly  two quants worth of free nulls, which physicists call relativistic mass, but which I call middle sized bubbles.

Color confinement

Multiply and two gluons which adds their wave numbers and you must get less than 91. By the time you get low enough to multiply, you are already in electron orbitals. Thus whenever you do multiply gluons, you have multiply by one of their small multiples, they call this color, I call it the number 7.  I have enough Boson possibilities to generate at least seven gluons. But, they only appear in  groups of three. So I dunno why they count eight gluons types.

Mass

They can't measure the mass because the nulls not packed and show no momentum.
I have mentioned the idea of gluon traveling waves, but now that I think about it, their bandwidth, in  motion might exceed  the capability of the vacuum. The top wave number, 7 * 13, can only exist if it carries free nulls equal to 13 orders down.

Here is another way to think about it.  The wave number for the proton has to count out its error, not more, and that is 19 bits at the speed of light. That would be the limit of quantized wave motion in the thing. However, if all gluons have to agree on the quantum number for the radius, color confinement,  that number has to be a multiple of three digits, and the top wave does not have that. And I doubt any other combination will do better.

In other words, the current model assume each gluon has a power series for their version of radius, independently.
Hmm....

What do I mean, adding exponents when making one power series from another

Its a bit of a cheat.  I am saying the digit sequence we need is a composite, the upper order digit sequence has N bit and makes a power series from sequences of lower order, M.  The total number of digits becomes M+N, when normalized. Maximizing entropy is the same as minimizing the number of digits. The vacuum always adjusts to make maximum use of digits.

Did I find my Gluons?

In the previous episode of mystery quarkathon, I was looking for Bosons to make the near perfect sphere. These Bosons  make two power series, one a seven digit sequence made of the other seven digit sequence as in [7+6]* 7 = 7*7 + 42 = 91, the wave number I need.

I found them on my spectral chart, two bosons but they are off by less than a third of a wave number.  That is the matching wave numbers were both one off from a multiple of seven. But wait, didn't the electron agree to carry imbalance, half its weight in wave, and upshift all wavelength by pi/6? Let me see, my wave numbers are in plain old Planck actions, relative to mass. So, if they are off by a third, then in wavelength that become:
3/[2*pi], or less than 1/2,  my how nice of the vacuum. So I get my two bosons at wave numbers at 84 and 77, or 7*12 and 7*11. I can see right away the Neutron, with no charge, will make an oddball isosceles triangle and wither away.

I apply the miracle of Boson arithmetic.  I can dump bits by shifting left and let the quarks compute whole numbers, and make power series from other Bosons by adding exponents.

7*12 = 2.[7 + 6] The decimal is two fermions in action and the six is two other bosons from somewhere
.
 7*11 = 7 and 11 The 11 being  Phd students working on  God's prime number.

So I get my  [7+6]*7 = 91

Now, you can count down and let the fermions packed nulls make fractions and bosons make whole, we don't care.

What do we do with 11? How about letting the quarks have the same spin? Then we can divide that up with worrying the extra fraction. Its possible if we keep the quarks separated by, say, the triangle function?

But I am not done, tune in for episode three of mystery quarkathon.

Tha maximum sample rate of bubble

Consider the proton with mass/wave number:

(3/2)^108 and (1/2+sqrt(5)/2)^91


The difference between these two is 9.288E-5.  Now mass adds, light multiplies. So mass can take out that error as is, and we get the log base mass of the error  = 22.9 and light needs to remove the square of that error.  The log base light of   (9.288e-5 ^ 2) base light speed, 38.6!.  But along the way, I see that we get a couple of bosons, where two wave numbers can match a mass quant.  Each boson divides thru the number of digits we need for light, and subtracts one from the digits we need for mass.

I know the next solution is mass 127, light 107. I need To dump three digits of mass and divide out 38.6 into 16 * n * m * k).  In in fact have three opportunities to make three bosons, I get a boson every time I dump a mass. But none of these combinations work. So I can say the 127,107 define the density of the vacuum.

Wait, you say, you cannot define the universe from your spread sheet!

Well, I can say that light is not a convergent power series of mass. Hence light will reach a maximum match and do no better. Do I have proof? No, the person who proves this is the guy going to Sweden, go find him. The person will relate the perfect sphere, group theory, and maximum packing theorem.

A process of elimination with the proton

Our conundrum:
Precision of observer plus protonic measuring instruments is less than precision of proton. So we are left with elimination all combinations which do not meet proton standards, and hopefully we will find the one remaining combination.

At this point, I am down to a slightly ellipsoidal wave motion counter balanced by an equilateral triangle of quarks in vibration. The neutron can't do it for long, its triangle is slightly off balance, so the proton does it, letting the electron orbits make the different, and any error there becomes waves in free space. So we have a limited set of possibilities, and we can eliminate them one by one.

So, this slightly ellipsoidal motion of the gluons is mixed with the equilateral gyro rotation of the quarks about the long axis with pressure against the forward phase.  This triangle has another mode, moving lightly up and down the axis to adjust its point of rotation. My best guess, so far; and we are exceeding the limits of my volunteerism on the subject.

Why do bubble make power series better than me?

They start out quantized, and they move at the speed of bubble. So, for any crowd of bubble quantized at some power ratio, an opportunity to find room will be seen by them at the same time. The speed of bubble also keeps symmetry, so if one axis of symmetry is counted out by a multiple of another axis of symmetry, all the appropriate bubbles arrive in time. Its natural, the speed of bubble and axis of symmetry.