Did I find my Gluons?

In the previous episode of mystery quarkathon, I was looking for Bosons to make the near perfect sphere. These Bosons  make two power series, one a seven digit sequence made of the other seven digit sequence as in [7+6]* 7 = 7*7 + 42 = 91, the wave number I need.

I found them on my spectral chart, two bosons but they are off by less than a third of a wave number.  That is the matching wave numbers were both one off from a multiple of seven. But wait, didn't the electron agree to carry imbalance, half its weight in wave, and upshift all wavelength by pi/6? Let me see, my wave numbers are in plain old Planck actions, relative to mass. So, if they are off by a third, then in wavelength that become:
3/[2*pi], or less than 1/2,  my how nice of the vacuum. So I get my two bosons at wave numbers at 84 and 77, or 7*12 and 7*11. I can see right away the Neutron, with no charge, will make an oddball isosceles triangle and wither away.

I apply the miracle of Boson arithmetic.  I can dump bits by shifting left and let the quarks compute whole numbers, and make power series from other Bosons by adding exponents.

7*12 = 2.[7 + 6] The decimal is two fermions in action and the six is two other bosons from somewhere
.
 7*11 = 7 and 11 The 11 being  Phd students working on  God's prime number.

So I get my  [7+6]*7 = 91

Now, you can count down and let the fermions packed nulls make fractions and bosons make whole, we don't care.

What do we do with 11? How about letting the quarks have the same spin? Then we can divide that up with worrying the extra fraction. Its possible if we keep the quarks separated by, say, the triangle function?

But I am not done, tune in for episode three of mystery quarkathon.