Thursday, May 1, 2014

Tha maximum sample rate of bubble

Consider the proton with mass/wave number:

(3/2)^108 and (1/2+sqrt(5)/2)^91


The difference between these two is 9.288E-5.  Now mass adds, light multiplies. So mass can take out that error as is, and we get the log base mass of the error  = 22.9 and light needs to remove the square of that error.  The log base light of   (9.288e-5 ^ 2) base light speed, 38.6!.  But along the way, I see that we get a couple of bosons, where two wave numbers can match a mass quant.  Each boson divides thru the number of digits we need for light, and subtracts one from the digits we need for mass.

I know the next solution is mass 127, light 107. I need To dump three digits of mass and divide out 38.6 into 16 * n * m * k).  In in fact have three opportunities to make three bosons, I get a boson every time I dump a mass. But none of these combinations work. So I can say the 127,107 define the density of the vacuum.

Wait, you say, you cannot define the universe from your spread sheet!

Well, I can say that light is not a convergent power series of mass. Hence light will reach a maximum match and do no better. Do I have proof? No, the person who proves this is the guy going to Sweden, go find him. The person will relate the perfect sphere, group theory, and maximum packing theorem.




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