sinh(1.5 * ln(Phi)) = pi/4 with an error of .0007, well within the fine structure.
tanh(1.5 * ln(phi)) = 1/phi = e^ln(phi)
tanh'/tanh = 1 at that point.
So its all right here, the connection between e,pi,phi. This is it, the constants of a finite set of things in a crowded environment. And it meets the conservation of quants, energy and mass. The set of angles are the Schramm-Loewner indices. It is Shannon band limited. It is the theory of everything, right in front of us.
How did it get the half angles?
It jumped to the third row of Wythoff. The half angle seems to be spin. This would happen if the quarks begin to ping pong between the two positive charged pairs. They would be a half angle out of phase from each other.
I am not sure yet of the sequence, but once the system has sinh(1.5 * ln(ph(), then it has Phi and has the Lucas numbers. It combines over two quants meeting the Shannon requirement, a two period look ahead as banker bot would say.
Our proton is cannot multiply, so it must have generated this sequence:
tanh and tanh^3, and combining them while the Lucas polynomial is within tanh'', which is kinetic. I am staring at my spreadsheet, and it is clear that the constraint is met at the half angle when the sequences add across the full angle. That is one unit of charge and one half angle of spin meeting the flow conditions. I will take a bingo on that one, thank you, just e mail me my Swedish banana.
That is, the Lucas polynomial, adding variance about the angle, makes the weiner motion. Hence there must be a sequence of the two powers of tanh generated somewhere somewhere in the Wythoff, and I have to hunt it down. Making that tanh sequence is the Higgs effect, and finding 1.5*ln(ph) must be the vacuum expectation phase.
I am very close here. In logs, the flow constraint is:
log(sinh) - log(cosh) + log(cosh^2), and these are accumulations of the tanh or coth values up the chain. The tanh'' is a bunch of things happened and thing not yet happened on the unit circle, so it has the potential and kinetic energy within the Lucas polynomials as it varies the circular angle. But that set of combinations, some not yet happening, has to be log.
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