They have dual curvature, look like odd shaped eggs when we add circular angle. Different energy levels, they superimpose. The proton should be a superposition of all three possible quark sets.
And that should fix the possible magnetic moments, making a Lie group. A 2 by 3, in 3 relative prime sets. The attempted fourth axis is a centered rotation, almost. It should have 17 + 1 positions if we include circular error band. Our three relatively prime eggs transpose inte on of the other two energy states. It would do so by swapping the negative curvatures, each of the prime set identified by the angle of their negative.
Te numbers work. We get 17 proton modes taken 2 at a time including the error of superposition.
6 * 17 *(17 + 1)
There three set, and their negative spins, to meet the Markov condition using three relative curvatures, we have created violated spin symmetry. Any reversal of spin select another of the three sets, or its negative. The gluon is flipping a quark once per error cycle. It is like a valve system in a three piston car. The gluon rotates about an uncertain toroid exis and then curvate excedds it flips the two adjacent quarks. It has to take two angle steps to the next link and adjust its valve. It has a symmetry for kinetic energy, little eddies,around the magnetic center pole.
The number 2 * 3^2 is simply the statement, each of three modes taken in all possible combinations, except they have two equivalent forms, negative and positive. 3^3 is simply all the possible combinations of three. There is no 3^4 because we are a algebra of finite sets.
17 is the number of terms in one binomial when three are approximating a bell curve as 18 terms.
In other words, the variance in circular angle is conserved. Any time the proton shell exceeds a spin deviation, one of the quarks will flip. They are constantly flipping.
That 17 modes are the usual orbital energy levels until we need to collide protons and neutrons and get another pseudo axis to partition kinetic energy levels again.
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