Well, half those bubble our outside the mass boundary making charge. Inside the mass boundary cold moves are winning the Whythoff game, so they out number hot spots by 2/1. The sphere likely goes all the qway to quant six to get pi^3 and that makes the sphere. Then it is subdivided by quadrents as the hots spots spiral through and so, in the end, you will see that even though the number or powers across the boundary is small, the total number of bubble will compute e^ln(ph) with a 16 order power series. The sphere is likely the building block of the rest of the proton, and I think it will have spin. It is should be Planks constant.
quarks just look like Pell numbers which sequenc as:
Pn + 2* Pn+1 = Pn+2 . So we can see that we need three quarks to do this. Then taking the small sphere, powering up to get leptons, then going to Pell in the nucleus all the quants add up and we get our avocado. Cols position at half the ratio outside the sphere where hot positions at half the ratio. We never really get the winner in the Whythoff game as that would be zero, and dx ->0 never happens, except in Newton's grammar.
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