In an unencoded sequence, i is the relative frequency of some event, where the total number of i =1, one event per measurement. In the encoded sequence, frequent events have more redundancy removed and have smaller symbols -log(i), quants, which is larger when i << 1 and smaller when i < 1.
But, Higgs have larger quants and appear more often in the encoded sequence?
It the multi channel effect. The vacuum separates out the sequences, small to large going out. The vacuum, because of its simple mechanism, moves all redundancy out of the first channel, which is the channel with the largest quant and smallest wavelength. Then it encodes a larger wavelength sub channel having a longer sequence, and gets small quants (larger wavelength).
The sequence we see is a composite sequence, and is the sequence in which every phase is equalized over the system. If the Higgs has wavelength 1, the next sequence has wavelength 3/2. The largest complete sequence has two Higgs waves and one of the next largest, it is size three. Higgs waves appear twice, the other once to make a whole sequence.
We can see this in the energy levels, Higgs having the highest SNR, which is energy. In a k order system, the SNR values go as:
k*.26,(k-1)*.26,(k-2)*.26
So a complete sequence will see a great many more Higgs waves, Higgs having the largest SNR.
As an exercise, one can compute the quant sizes on a per channel basis, the SNR being k*.26, and so on; or one can sum the SNR and compute the whole group at once using the ratio of one SNR to the total. The relative quant sizes between orders remain the same. So this works as expected.
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