Using impedence to do Kepler Laws

Lets skip quantization for a moment. Using impedance we want a mass to roatate around a point source of gravity without wabble. So we want impedance to be match velocity along the route.

 When using mass,Impedance of an object is the rate of change of flux in the 'field' to the rate of change of flux of the moving body. If that impedance changes, then velocity changes, as in Maxwell equations below.

 C0 is the velocity  of the orbiting object, in this case.  So velocity = Z0/U0. Since the object always has the same rate of change of flux, let z0 be normalized to 1, then U0 is the rate of change in flux density of the point mass generating gravity. It goes at 1/r, because we are not using force, just Kepler laws. It rate of change is relative to the angle of the orbiting object to the flux.

Using congruent triangle we can see that velocity moves us along the tangent of the orbit in one second; in A1 and A2  gives us the hypotenuse along the path. for one unit of distance. Kepler says those triangles must be equal in size. So we have derived Kepler very simply using the concept of rate of change of flux of one body relative to another, impedance.

I did this trick to demonstrate to myself that impedance is a general concept, and we can use it our quantum system for kinetic energy and wave, both. Also, we have a good definition of right angles when it comes to phase equalization. We can make gravity waves and so on.

Does the Sun, then, have a gravitron in the middle? No, they are orbiting around the periphery so0mewhere.They are tiny, have little mass, and large wavelength. The gravity we see is actually much of  kinetic energy of all those protons that  was removed when the Sun compacted. It is the common mode kinetic energy. The Sun actually should be emitting more flux as it cools, and the phase gets stabilized mostly outside the Sun center.