Why Avogadro's?
Imagine walking up the Markov tree, and you are segmenting spherical angle according to spin count.
You have a null at the center, the spot where disequilibrium operators went to to die. You reach a point of maximum precision, The surface appears too flat for light steps. Light needs ti dump one deviation for each local region being the 1,2,5. I needs to have at least one deviation difference between the middle and outer counts. The Planck affect.
Quarks will not close a surface.
The is a count of 3B in one of xyz. But that makes 9xBz a termination but there is no solution for x,B,z, none among the real positive integers. This is a request for the snake to make crossover holes.
Not in this dimension, sorry. But I can see that three would be the alias dimension. The proton has an N mismatch which causes its external reactions, especially the magnetic moment. And beta decay. Spin is flipping in and out via spin crowding and making short term photonic reaction. Two snakes, not enough N. One of the snakes, at a time, get segmented bosonic then retrace fermonic. If the snake cannot close then the two ends leave a spin moment, and other one end has spin collision and reverses countt. There will be a lot of reverse curvature.
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