Thursday, May 21, 2020

Conservation of deviations

We can imagine our beach ball was perturbed in shape by some unseen equations in 4D. This causes a gap in the coloring sequence, the operator first puts sin colors close, and becomes momentarily a boson. That forces conservation of count, the quark system us conserved, and must make a corresponding adjustment. He has a scheme to alter the knot while conserving total N, the number steps around one cycle of the knot..

Then do this for all layers of your beach ball according to the previously known distribution of perturbations. You get the combinatorial when it happens. The combinatorials we want are when it happens twice because then we have completed one subsequence sequence with the operator.  The conservations of energy simply means neutral state is when events are sampled twice. The diagram counts events that restors equilibrium after being tipped off balance by a spin interaction.

Assume we had an outer surface of a sphere.  We are up the tree, we have a have color operator, but we still count six times around the deviation sequence. Perturb that surface and the operator can likely hold a double spin a few extra steps via finer resolution. That would be inertia, or mass.  It is also resolution.  Quantize mass as a relative ratio of color operator size over the volume.  Actually we would be counting jumps up and down Markov.  Get the distribution of mass, find its singular point and call that the center of a sphere.  Then integrate up the equal lines of resolution without overlaps. This would br quantized in R and assumes spherical symmetry. From there set a rectangular axis and integrate the masses along each of the verticals. You could repeat the procedure all possible orientations of the axis, then partition those in t, might be fun. t subject t conservation of N.

Time is really the sequence of rotations about the center, over a finite radius. The center has probability zero. Time is quantized so transactions are -iLof(i). Events are ordered by the shortest path to the next rotations along that summations. Ditto x,y,z.  Motion is the change in operator position per unit time.  The quantization of time to spread the number of light steps was the relativity adjustment. Quantizing space insures that mass is about equally dense.

If you are on a flat surface watching the edge of you beach ball rotate, you can see that at the edges, most of your paths are merged into the stereoscopic view. Time will increase in resolution, and that is what slows you down. It is the quantization effect of trying to spread actions over 4D space.

Kinetic energy is the other party's problem, the one creating a rectangular axis.  The actual number would be the deviations from a closed surface, as given by a deviation in count, N.  That is what force movement up and sown Markov. The operators obey natural law of integers.  They have to if we assume a plank and light steps.

But once we have an x,y,z,t then we can buy engineered built machines and predict what they should measure, kind of a cost savings measure to live in a flat world. You can use high powered finite element counters.

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