Spin causes curvature

The simple fact is the color operator is always carries a deviation when spin is 1 (physicists call this spin = 1/2, as they assume a zero).

Every operation leavers a one deviation  from zero. A spin of 2 simply means the operator will traverse the sphere twice before coloring, it will recolor. The spin two increases curvature. Or spin two will color two spheres simultaneously.

How did the quarks get spin 1 (spin 1/2).  They are not a sphere in their composite.  I am not sure even odd spin is what quarks doing, they have three different spin modes. The physicists got this a bit fouled, I think. Quarks exist because even odd spin would not fit in the null. If quarks had evern odd spin they would not spiral together on exit. Their spins are partitioned.

My guess is the spin term gets passed around to the quarks. Light cannot keep up in one quarks and  the spin deviation gets passed.

Spin in curvature. The quarks cannot get enough surface area to cover a deviation. The result is the constant passing of curvature. Constant spin interactions between quarks is really quarks constantly changing curve to hold the deviation.


What about charge?

I am not sure my deviation count matches with the physicists definition of charge.   The 1 2 5 system has two options plus rollover for the middle counter. If that is charge, then one charge is two deviations.  So the proton, really dumped four deviations counts. How?

1,2,5 requires six light interactions to limit Plank's deviation.  If the quarks could partition then they can have the 1,1,2 mode operate independent in three quarks. They will place four more deviations, but their surface area will be more cylinderical and open. Instead of light being late to the game, it is now ahead, via partition. The proton is actually smaller than we think.  The open shape aligns spin along three moments to eliminate interference.