Plank is a quanta

If the single point deviation, Plank, is hree, then what is the aggregate count of tinys Plancks spread around.  Plank is quantized, count then up.  It must be (3/2)^k in the 3D system. They must be the number of deviations in the entirety of contained kinetic energy.  So Plank quanta times obect count yields all the potentially useful notches on the 3D rulter system. This is the entire statistical basis for thermal dynamics.

But the electron is the thing uneasily measured, and it is the enclosed surface that has and aggregate deviation less than three.  We cne pick of the epectron Markov node, andthe number, as an exponent fits.

So there is a Ploanks aggregate, an equivalent Avogadro that a fills in the unmeasureabel space. We can use Boltzmann, and I think that means treat it at the 3D sample rate.

The fine structure counts the number of paths between integers over a complete Avogadro. These are minimized, appear as bound noise to the instruments. It is the boundary between surfaces in hyperbolics. It is like the space between perfect spheres, which is the Avogadro assumption.

We measure the proton as the reflection of the entire sphere. At an integer count of 1836, it is an exponent, let us divide out the total number of unmeasurable planks via subtraction we get 1699, a prime. This must be the total number of measurements made by the system. You cannot draw atomic orbitals to a resolution greater, and this number is the sum of all the deviations of the filled Markov nodes.

It is prime because physicists do a good job mapping to flat earth. They have reduced the symmetries.  Into local force equations. Then they get a flat earth single centered model, and the entire sample space is indexable. The residual round off is further research.

In other words, the vacuum has to be both quantized and follow thee rules of thermodynamics.