Integer resolution

I want to fit my binomial into a know number of samples, i.

My number per set if the matching ratio, a number like six, maybe.' My log base six just tells me I ca count to the nearest sixth.   The ilog6(i) tells me my maximum integer count.

log base x is the resolution of x, we can think of it as 1/x in the round off.  Log really means number of trials per count in the given base.

Sampling which is imposing RMS rules, the sample error is reduced more than half. It simply proves the binomial at x^x max is the best fit to Gaussian as  N going to infinity. In other words, step one and prove that continues.

i, the number of deviations is finite for any closed problem in integers.

In Markov triples, xyz are the number of error paths between two integers. The total sample space is one of each set, taken once, is 3 ^ (xyz).  One each for the next error correction. x,y,z the set sizes for Markov solutions. They are deviations between integers. Dropping a dimension allows us to prove a bunch of stuff in two tuple, sometimes, as N gets large.

There is a one half in there somewhere. The solution squeezes N so Einstein, Planck, Boltzmann, Avogadro all work, in integer.

Then one can show ha if - iLogi) is met for each of a triple, then it will be met for the Markov tree jumps. The full n-tuple system should meet all requirements for maximizing entropy. The proof is showing that counters close to one can e mix and matched to get counters close to one.

It seems to me that base, three, will run into a problem counting the most severe irrational. Entropy is not maximized for any step forward and maybe it jumps to a 5 tuple. The vacuum has integer bandwidth.

Kinetic energy is an N shortage, not enough vacuum to keep spin interactions idle. So closed surfaces act like they have a bias on the color operator and move along an axis. At some point the N density match a stable Markov point. This is an aliasing problem.

Spin interactions occur when N too dense and the temperature effects restores -iLog(i) by segmentation along the spin axis. The separate energy ;levels will restore -iLog(i). Plnks curve shows the adaptation process, maintaining segmentation under temperature.