Matching spiral moments?

These are the things below, the denominators, which come out as spiral rates from the center. When they product is 1 ot within precision of 1, the surface of the object is marked.  Each time a prime group is added the 1 points obtain one more line of symmetry.

 Look at this paper by D. Pozdnyakov. But these are counter posing spirals for each prime which combine with the previous spiral moments. Its all about splitting up the curvature to accommodate sphere packing with multiple spectral modes, each mode independent of the other, so they can superimpose.

Each prime has the form p + 1/b and p -1/p.  That creates a counter posing dual spiral. With one prime, terms cancel only on the sphere, with the second prime 2 sphere are formed by term cancellation, with three, 2*3 spheres are formed by cancellation.  I am pretty sure this is what is going on. The more energy, the more modes, and these include much smaller fractions, meaning higher bandwidth, making for more points of cancellation. A discrete, radial  power spectrum designed to encode as many Nulls as possible, that is, put them into separable groups. In this systym, the phase imbalance in the proton center is absolutely minimized, so the proton lives for 10E34 years.

Schrodinger and Heisenberg describe this as the err function of the engineering approximations, and got it right, mainly because the engineering approximations are damn good, especially charge and magnetism. Uncertainty, imprecision, is still the main component of physics; its just that the value of imprecision is always put in engineering terms. But the true uncertainty in this system is the band limit defined by the finite system under minimum redundancy grouping. Go to Pozdnyakov's paper where hhe found the zeros of the Reimman, and remember, these are near zero. So trace out the small boundary where all the near zeros has the same nearly zero value.  Invert that boundary and get the orbitals.

Another way to do this is to take an X axis of unit length. Mark all the whole number primes, and the 1/prime fraction, up to the center of the atom, about prime 13.  Mark them to a precision of of 1/Higgs 1/sqrt(Higgs) decreasing out on X. Then spread out the x axis to a circle, reducing the precision again by 1/Higgs 1/sqrt(Higgs) , decreasing out  then to a spheric volume, reducing precision by 1/Higgs 1/sqrt(Higgs) decreasing out again.  Then look at the ruler, and mark mark the spots where every prime whole number lands on the same integer.  I think that works.