Can Albert help me?

Here is Albert's formula for the absolute zero temperature when Bosons act sleepy.  Why does he have the two thirds in that Zeta function?
Because he wants to know the number of ways that particles can be at an energy state above the ground state. So look at Shannon again:

 When that S/N is greater than one half, then particles can be observed at quant C for bandwidth B.  Bandwidth in our scheme is temperature, and that comes out of the zeta function. So S/N is simply the half integer split between the ground state and the next state up for the given temperature B; the point when particles jump energy levels.

The Zeta function is the curve in the finite number line.  When it is straight, temperature is high, the number line is more accurate, it has more stable energy states.  Albert wants it curved enough so it just measures the first energy state, a one foot ruler, not a yard stick.

That does not help us directly, because we want to write the equations for the tiniest of things, things 10e-19 times smaller than the Bosons.  At that level, S/N is still the same thing, size, and it is still one/half, that is large. So my concern about the size difference between the two phase bubbles.  I need a ruler straight enough to measure from gravity to Higgs, but curved enough so the bubbles can make a proton with that large precision.

In our case, our equations are written from the point of view of a bubble finding its way among neighbors. One thing that does help us is equivalence.  Once we can show that all movements of bubbles can be written from the point of view of the null bubble, then things simplify. I think we can discover real quickly what the path function for two Fibonacci exchanging bubbles sequences look like. All we need to show is their ability to generate a geometric series that corresponds to 'isothermal' gradients, gradients where the contained disorder is equivalent.  That is easy. Then we show the most irrational number does indeed generate the next accuracy level for a new axis of symmetry.

But, size is going to be 1/2 different, and the size difference may or may not be that dramatic, but it will 1/2.