The Higgs mecanism, for example

91	9.22769139322099E-005
92	0.1575005387
93	0.3149088006
94	0.4723170624
94	0.3702746758
95	0.212866414
96	0.0554581521
97	0.1019501097
98	0.2593583715
99	0.4167666333
100	0.268416843
101	0.1110085812
102	0.0463996806
103	0.2038079424
104	0.3612162043
104	0.4813755339
105	0.3239672721
106	0.1665590103
107	0.0091507484
108	0.1482575134
109	0.3056657752

Wiki explains:

The Higgs field, through the interactions specified (summarized, represented, or even simulated) by its potential, induces spontaneous breaking of three out of the four generators ("directions") of the gauge group SU(2) × U(1): three out of its four components would ordinarily amount to Goldstone bosons, if they were not coupled to gauge fields. However, after symmetry breaking, these three of the four degrees of freedom in the Higgs field mix with the three W and Z bosons (W+, W− and Z), and are only observable as spin components of these weak bosons, which are now massive; while the one remaining degree of freedom becomes the Higgs boson—a new scalar particle.

In spectral theory, this is all about finding room in the spectrum for sidelobes in an under sampled system.So, you can see from my spectral chart, 107-91 is 16, a number the Higgs mechanism created, not me.  Higgs left the numbers 104 and 94 for spectral power, and the band limit is 107 with a significant guard band.

Why and how?
It broke symmetry with wave 90, 90+4 = 94, 94+10 = 104; and oddly, the matching mass number match 108 + 4 matches 94, and 112 + 10 matches 104; and they leave much more wave than mass, they will not pack.

Did the bubble do a rotation on the group structure? No, they just went to minimum phase quantization, or flew the coop and what was left was the best minimum phase power spectrum up to the bandwidth of the vacuum, 107.

On the mass number, 122+5 makes 127, and no group of five is being packed anywhere in a 3/2 universe.  The numbers ended up there because numbers that did not flew the coop.

So how did charge do the 2/3 power?  I am a little unknowledgable, but the vacuum has two modes in its 2/3 curve, and one mode did a phase shift relative to the other.

The power spectrum ended up back in symmetry, if you include the proton.

Did the photon end up massless? Well, you can bet there are unpacked nulls in the orbital slots.  And you can bet that any free wave exchanges with Nulls.  But the question really is, does a travelling EM wave move Nulls on net, along its forward direction? Not much, and beyond that I do not know.

This whole thing was about restoring a symmetric power spectrum in a 3/2 space. The wave number for the electron is 15+1/6 (charge asymmetry) below the 90, and the band limit is 17 above the 90. It works, and is damn near symmetric. For the neutron, its 16 and 16, I think. If the proton is 90, then it is 5*18, the quarks taking the five as a 1+1+3, and the 18 broken into a dandy little Nyquist minimum phase sampler with modes made of 2*3*3*3.

What did special relativity have to do with this?
In my model, nothing, because this is already a sampled data model. In the model using Isaac's rules of grammar, general relativity simulates a sampled data system by adding terms.

What does "acquire the vacuum expectation" mean?

It means let the bubbles hit the 107 number and bounce back.  It is an impedance mismatch reflectivity, or side lobes from under sampling in spectral theory. The Higgs mechanism describes an anti-aliasing filter, or an impedance bridge matching network.

Why don't they use spectral theory in the Standard Model?
They are, actually.  All those group matrices are done under the generic name spectral theory. Sampled data engineers use them too for power spectra. I don't, because I am lazy.