I can make these numbers

	ℓ = 0	ℓ = 1	ℓ = 2	ℓ = 3	ℓ = 4	...
n = 1
n = 2	0	−1,0,1
n = 3	0	−1,0,1	−2,−1,0,1, 2
n = 4	0	−1,0,1	−2,−1,0,1, 2	−3,−2,−1,0,1, 2,3
n = 5	0	−1,0,1	−2,−1,0,1,2	−3,−2,−1,0,1,2, 3	−4,−3,−2,−1,0,1,2,3,4

All symmetrical about zero. Normalized to integer.

Thye N quantum numbers are five because the proton gyro is likely going the:

 [1+ 1+3]*18 = 90

The L number exist because the quarks make a triangle. They are ordered by value, like a power series. I could jump on my Maxima and generate these pretty quick. Powers of 1,2,3. The key is to decompose the 18 into the proper order, then sequentially take powers of the component, multiply and continue so they are all generated along the ordered lines of symmetry. The proper sequence should generate a Planck's curve. The quant/sample rate should count out a digit sequence, using the most irrational number as a base. One axis of symmetry is easy, you have to neutralize the charge in the three quarks, everywhere. So, in a way, you do not even need to create the electron. Just apply the unitary exponent, 2/3,2/3 an 1/3 to the quarks. The minimum density result will always be the wave with the induced charge that counter balances. Increasing energy is equivalent to increasing precision, so more terms get added. Up to the electron limit, I think, wave 75. The gyro machine in the center has the 18, let is grow by its multiple multiple integer powers.

But there is still an oddity. I have the electron wave number at 75, 74 really with the extra charge. 74 + 18 = 92, one quant too many. The magnetic lobes, the M, should appear automatically on minimum phase packing. Their moments are built in, as long as the negative and positive fractions are separately quantized.  Now we are going beyond my know how. But the key thing, this methods computes all phase, none of it bottled up in an engineering model.

I prefer not to do it.  I want some young Phd mathematician to get the Banana, and I get the thrill vicariously.