Bell simply proves that free space is finitely subdivided

Consider three (highly correlated, and possibly biased) coin-flips X, Y, and Z, with the property that:

1. X and Y give the same outcome (both heads or both tails) 99% of the time
2. Y and Z also give the same outcome 99% of the time,

then X and Z must also yield the same outcome at least 98% of the time. The number of mismatches between X and Y (1/100) plus the number of mismatches between Y and Z (1/100) are together the maximum possible number of mismatches between X and Z

A lot of not too much. The whole point of quantum mechanics is that space is finite, even Einstein posited the finite 1/2 quant of vacuum energy. The whole debate came about because continued subdividing should always yield the same result [if the vacuum was an infinitely subdividing integral performer].

Can the physicists measure the probability, or finiteness of the vacuum? You bet, look at Avogrado, a .037% error.  My numbers say, that number lands right at quant integer zero. That is the vacuum doing coin flipping.  Will physicists ever be able to watch a vacuum coin flip up close? Never.

Is there spooky action at a distance? No. At some 10e54 samples per second, and the accuracy of Acogrado's number, we can never separate the observations.