Then we have the electron wave number

75 + 17 = 92, take away the 1/3 of electron mass (1/6 of its wave) which is devoted to phase imbalance, we get 91. The 17 being the exponent of the constant that appears in the proton/electron mass. So, the physicist fires an electron, with exponent 91-17, at the proton who then returns that difference plus its own null  exponent.

And we learned the proton is doing something in quants of radius because the proton gyro machine likely wants to keep volume/surface are minimal.

There, finally I am convinced where the electron sits on my spectral chart.

What is the electron precision at that point? .009335. What is electron null number? 89.  Wave 75. The errors on either side of the Compton pair are in the .14 range.

Thus, without a doubt, my spreadsheet is correct, since it computed the electron number out of thin error well before it computed the proton numbers and the reversal of causality is impossible.  The proton and my spreadsheet agree on the universal digits. Both my spreadsheet and the proton discovered the number 17 independently, neither watch Sesame Street.

And, the proton gyro is, in fact, a volume/area minimizing machine with six degrees of freedom, about a center, three bubble sizes and is uses hyperbolic functions. We know it uses hyperbolic, because we know it is governed by its Shannon orthogonality, the hyperbolic are solutions and are positive in their Taylor series.

One could work the problem both ways, wave or null, using 2/3 as an adjustment or 1/2+sqrt(5)/2 as an adjustment.  The proton, nor my spreadsheet cannot tell the difference between rational and irrational fractions.

That means we need to find all the gluon/quark pairs within that range. Three times 7 is 21, (in Null) we are at the edge, so the quark gluons are definitely sharing three slots apiece. and your quark transformation matrix will be measuring the shift between one slot pair to another. The diagonals will be the total precision of that shift within the three slot pairs.Physicists will call the three sets color, and the shift will be up/down charm/strange and top/bottom. Since it is a total three slots per, the charge, being the amount of phase difference in the wave shift, will be in units of 2/3 and 1/3.

And, the proton is working with the electron slot pair, we still have to fit the X/Z Boson pair in there somewhere. So my guess is that proton thus booted the magnetic slot and used it to carry the one.

A big clue:

As long as the proton is making wave outside its radius, and stays within its precision, it can borrow wave numbers above its nominal 91, but below the 107 point. Look up there, there is a fine and dandy little pair of slots that could make a couple of Bosons to connect nuclii. ANd, the wave number, 107, I define to be the Higgs wave, it is reserved for the quasar.

Hence:

Using the power of prime numerology, one could take the difference in exponents at, 19 Null (108-19) and (92-17), add in the borrowed magnetic slot,  abd borrowed slots above 91, and construct a twos digit system and do all your computations in that.  The twos system will count out the total precision when done, and thus verify we have an Avogadro. 

The fractions in your twos binary system should count out a dandy periodic table.

Furthermore, I predict the quasar will make lots of negative protons, and the baryon jet will spew all baryons types, the positive protons dropping out first, the neutron getting trapped in heavy gravity, and the negatives making it to the top; like a massive mass spectrometer.