Sunday, April 13, 2014

So, how do mega orders affect my colliditron?

Not much. We start with 15 bits of precision, and calculate to the edge of gravity, and get the periodic table.  Drop three bits, and count out the types of star systems, getting the periodic table of  planets, drop three bits, count out start clusters, drop three bits and count out types of galaxies. Then we drop three bits and get the universe, I suppose.

Wiki says there are are probably more than 170 billion galaxies in the observable universe.[8]  That would be 63 orders in our 3/2 scale, the baryon number preserved all the way up. . That is about where the periodic table appears in the first mega order, though this is a very inaccurate estimate. At the level of the universe, the 'quark' matrix should be a scalar, there is only one type of universe, mainly because the universe has nothing to compare itself to.

We run into problems interpreting red shift if quantum numbers are stabilized at the galactical level.  Light would not only curve, but would be decomposed into the spectral map of the galactical field.

If this holds up, then there is some fundamental relationship between the Baryon number and counting systems. Probably addition has to be conserved and 1+2=3, in any counting system. So when we take something to the limit as dx approaches zero, we will violate conservation of addition and fail.

The sample rate of light is the invertible multiply function for groups. Groups grow by mega order and the addition function becomes as accurate as light, light no longer functions as a mediator.

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