Make a perfect sphere with a couple of up and down and three gluons

That is the puzzle we have to solve.  The proton , and neutron, are the gold standard, they have to be near perfect spheres.

The gluons come in threes, but they have color white, so I bet there is an isosceles triangle involved here.

There has to be a sperical wave mode and two angular modes supprted by the gluons.

The sphere has to be very flexible in radius for the proton to be so perfect.

Is it possible for a bunch of stupid bubbles to make a fixed isosceles triangle in perfect rotation?

Well, just taking the top wave number, 91, or 13-7, what is the beat frequency? 6, make that two wave modes of 2 and 3, all in powers. There is the key, the perfect spherical multiply system. The one wave counting out area, the other counting volume and they always match.

Multiply efficiently.  The vacuum only does powers series, very simply because he makes Bosons which move.  So it is dealing with:

r^[13*7] so it makes a Boson the packs in a 13 digit number, then uses that to make a 7 digit number.  Each digit sequence is a power series.  Multiply become very efficient, and it can do big things at the limited speed of bubble.  But if it gets a natural interference term like [13-7] = 2*3, then more accuracy. It needs to cover the total accuracy of the proton, 9e-4, it has to make wave modes that construct a sphere to that accuracy on volume/area.  If the combination exists, it will naturally equilibriate to it. 
So, [7+6]* 7 = 7*7 + 42

What is 7 *7? A seven digit wave counting by powers of two. But that no problem for the Bosons, that is their thing, moving about with two adjacent wave numbers, like the EM wave. That is your radius squared, a spherical wave mode.  The 42 is 7*6, the radius, with the 6 used to support quark orbits.

Why this is so simple even a bubble can do it. The first wave modes counts up with the 7 powers, the second gets with the quarks at 7*6, using the radius as a base.  The quarks are on the surface, counting out a 2-3 pattern in the null points of this surface wave.

So, I need to look on my spectral chart and find two wave numbers, one looking like 7*7*j and another like 7*k, that match two adjacent null quants that  make dandy bosons. Hopefully the j*k have six as factor.  Tune tomorrow  for mystery quarkathon!

I bet  there is someone out there who is going to crack this case, within the next few months.