It is the extraordinary simplicity of physics under the Theory of Counting Up. The vacuum must, at some point, get out of balance when doing everything with such simplicity. They have to reach the Higgs limit where the next group is bigger than the density of bubbles and they have no subtraction operation.
I dunno how this happens, I must think like a proton, a most difficult task having trained myself to keep an empty head of vacuum. But protons likely drift to the fringes, as the centers reach their Higgs.
Protons show a positive charge because they bury negative phase, it is the opposite of what we think. They would disintegrate rapidly at the fringe where large positive bubbles dominate, cause a recycling, somehow.
To us it would look like interstellar space is expanding, but what really happens is a slight density gradient, the volume of space constantly realancing by moving protons from the center out. The circulation time determined by the density gradient which supports the proton.
We would be less than rectangular on the larger scale, the lack of perfect symmetry explained, and the vacuum always having just enough SNR to make the round trip. Proton would disintegrate in interstellar space at just that radius when the balance of {-1,0,-1} bubbles drops below the Plank volume. That SNR must include the density of protons needed for the circulation.
Since we can calculate the density of the vacuum, we can compute the SNR needed to climb the quant chain and thus compute the difference in volume size of the three bubbles, and then compute the size of the universe.
The size of the universe being that point in which the little bubbles do not have the precision to compute sine(theta) to the third power in their Taylor series. That precision should match the precision of the Higgs number:
(3/2^108)=(1/2+sqrt(5))/2)^91
And physicists would add the isotropic adjustment term to the Einstein equation, thus making the world static and slightly curved. The cycle time would be relative to the Higgs limit, so if energy was lost, the cycle time decreases but who would notice? We are not looking at galaxies receding at some velocity, but galaxies some curvature time cycle time.
How would this effect show up in space?
The red shift in space would match the rend shift in sign(theta error, an when those match, the velocity of space expansion equals the velocity of galaxy compaction. The cycle is connected. Proton recirculation is continually replacing the volume lost from compaction with the volume gained from expansion.
The universe need only have enough supernova explosions to keep the proton balance constant. In any region of space where the gradient exceeds the cycle time, matter packs to the Higgs limet and new protons are made. Regions where the gradient is too small makes small matter which dissipates toward compact regions.
So, physicists are correct about the Big Bang time, just incorrect in its interpretation, it is the cycle time. The universe would look exactly like it began at an instant, having no way to differentiate.
I will take a wild guess. The apparent size of the universe and the apparent big bang distance are related by Pi.
No comments:
Post a Comment