Compton wave length and space impedance

1836 15.6175392619  log(1/2+sqrt(5)/2)
377   14.6307168455   log(3/2)

If I have the theory right, then then light should sample the mass of the proton at the same rate as mass samples the space impedance.

They are off by one wave number, mainly because there are adjacent mass quants at the point where the electron orbitals start.  How does the proton know all this? Because when one of these phase imbalances began to quantize the proton nulls, the proton nulls rumble, they tell the proton that phase imbalance is about to go Shannon.

The proton is going to be sensitive to space impedance because the charge it, and the electron share is related to keeping wave from quantizing a chunk of the proton nulls.  

I am looking at spectral lines from the atoms.  Now all of these should go as natural log, they are emitted before they go Shannon.  Their frequency of emission and the space impedance of 377 should be should be aligned, for the same reason. The frequency they emit at is energy, and the mass they match plus that frequency causes the same rumble in the proton phase imbalance.

I am pretty sure the Phase/Null ratio for the electron is 1/3. It is the quarks, then, that are setting the null ratios counting down, they are not set counting up from vacuum noise. Another  blunder of mine, one of many.
But wait, that cannot be, it must be the other way around since everything is constructed from the set {-1,0,1}, in ratios 3/2 and managed by the sample rate of light, which is Fibonacci. There must be a connection I am missing.
So, you put a heavy muon in the middle of those orbitals, the rumble point changes.
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