The thing that makes the atom work is efficient packing by the quarks. The mass quant at the proton is 108 = 2*2 *3*3*3. No matter how wave moves, the quarks find an efficient packing. That makes the proton attractive to phase because of its excess capacity to balance phase variance. So we get a dearth of free nulls in the outer ring, and kinetic energy is supported, hence the atom. How would the proton use this capacity? By allowing phase to move in and out in response to energy changes.
There are seven principle quant numbers, and about 14 missing mass quants from the electron to the proton. There are some 11 missing wave numbers corresponding to those missing mass quants. There are an additional 7 angular momentum orbital slots. The angular and principal split the slots available. Count up the vectors of principal and angular. Some eight. These sets of angular and principle are the contours within which the proton can maintain constant precision, and none of the wave numbers in the atomic shell will materialize.
These lines lie along an integer defined manifold of phase variance in the proton
That is the plan, find the curvature in which that happens.
And these integers, the first three quantum numbers, should be separable into an integer set, i,j,i*j which define the equal potential contours in the proton. There exists some integral equations that tells me so, and proton precision should be allocated so all those integrals converge uniformly with integer summation. These phase potentials should all be equal gradients, and they should have simple errors with respect to the main quant wave numbers up the quant chain from the atom. The proton seeks to maximize instability of the Nulls and maintain stability of phase by accepting phase imbalance.
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