Notes on twos counting and Fibonacci packing

First, a reminder.  When we look at a twos bit number and finsd the -iLog(i) for each digit is within one, we mean that for i=2, it appears 1/2 the time and has quant ratio 2.  That is the encoded version, not the priginal bit stream of phase/null.  The phase as packed all the small quants into groups and has given us the encoded version, but in counting up that actual phase elements, there really are quants at ratio 2 appearing twice as often as quants of ratio 4. We really are counting twice as many phase groups in the real world, just using encoded bits to do it.

In the case of hygrogen, there really are a whole bunch of electron orbits, relative to out single proton, even though the electron may have only one wave number. When we scale up, we get a twos number like: 110000100100001001. The 1s are the subgroup counter, and it has all those zeros available for slots. The first two 11 are the proton wave/null quants, and are together, they Fibonacci pack, they mark the integer one. for one complete group. The other sub groups always come in pairs, the first one is the wave number, the second is the null number. The zeros in between are slots available for kinetic energy.

Now we are counting by sub groups, the electron wave number tells us how many times a slot appears in its group.  It the wave for electron is k and the null for the sub group j, then [1/(k-j)] [log(2^(k-j)] meets the Shannon condition. The sub group will coexist with the proton. The subgroup will appear more often, then is appears in the unscaled version.  But when it  appears, it appears with all those slots. We have scaled, dialated the bits to expose the sub groups.

This is Fibonacci packing, it is how phase organizes the vacuum.

But wait, that's not all.  Each group accounts for its fractional error, the amopunt by which it is not -ilog(i) compatible.  That fractional error packing looks just like the packing above, except it has a decimal point.  Where is the fractional error held? In the proton packed nulls.  If the atom emits two photons, they each take their fractional error with them in phase units.  One wave offset to the negative, one offset to the positive, relative to phase zero. Hence, the solution to the quantum entanglement problem. The fractional phase heads to the proton when it unbalances an energy slot. When you scale the system up again, you multiply by a twos power and part of the fraction gets moved to the lower orders as integer wholes, the subgroups now expand beyond integer and have to hold their own fractional component.  The proton is the unit of account in physics, it is the dollar, plus change.

All of this works for one simple reason, when it does not work, phase flies away and we have no structure to examine.  The same process works for the shoe industry.  When shoes are not packed properly, in their containers for shipment at various levels in the shoe industry, then they disappear, they become uncountable inventory, losses.

Higgs:

If you scale beyond the proton, there is only a wave number available at (1/2+sqrt(5)/2)^107, some 18 orders up, but you will expose all the gluon and quark stuff. You do not get the twenty dollar bill, just some 18 dollars and change.

I will get into the hyperbolic a little later and show how fractions are maintained.