Digits sequences, Shannon and grouping. (Updated)

I copied a partial list of the sorted quantization list below, both wave and null quantization. I will get to that in a moment, but first let's talk about digit sequences.

All Nyquist encoded digit sequences have the form:

r**n,r**n-1,r**n-2,.... where r is the base of the digit system, and n is the digit index.  This is standard derives from the fact  that Shannon theory is based on  a general Nyquist theory, in which the optimum encoding of values in that base will start with the most significant bit as r=2**n in a binary system. The next bit down is the previous divided by 1/2, and then next by 1/2 again, and so on.  This is the Nyquist result when any series can be sampled at half its rate and recovered.  The optimum packing, in that case, is a set of digits, each digit representing the component of the signal that varies as (1/2)**n.  When r is not binary, then do a change of base and get, again, the optimum digit packing. Let Br = log2(r) be the rate Br for an n-ary system, then we again get the binary system.  Note: log2(r**n) = n* log2. And log2(2**M*k) = m*k. I can compare the SHannon condition, even sotore the proper index.
(Note: I could have my change of base inverted here, and uncorrected)

2**(n*Br),2**((n-1)*Br,2**((n-2)*Br,....  

But the (n-i)*Br will have gaps when they are not multiples of k, where the k are the integers in the sequence: 2**k,2**(k-1)... So finding the nearest k = (n-1)* Br gives us the Shannon condition. These gaps make the packing, I think. That is my current look, working in twos to get the grouping.

But in computing output, I convert to the natural log, e, and hence use what they call the Qubit, described by Wiki. I get:

e**(ln(r)*n),...

Nulls and wave mix together in Fibonacci packing, I am sure. But, it matters no, I extract the backing in digit encoding.  I take my driver signal, and take the natural log, then my quantizers can do compare and subtract.

I mention this because the list below is set up that way.  It is the two digit systems interleaved, one for light and on for null.   The type of digit is the left column, the log base 2(r) on the right.  Look at the type of digit, either r = 1/2+root(5)/2 or 3/2.  Note that there are two spots where the wave mass quantization appears twice in a row.  These appear throughout the 108, (r=3/2), bit sequence that make the smallest volume of integer vacuum.  These are the group separators.  I have marked them with the 'xx'.   Those three marks will be the quarks, as this was taken from the most significant digits.

1	0.2120778677
0	0.1027984548
xx  1	0.1027984548
xx  1	0.0064809581
0	0.0064809581
1	0.115760371
0	0.115760371
1	0.2250397839
0	0.2250397839
1	0.3343191968
0	0.3343191968
1	0.4435986098
0	0.4435986098
1	0.5528780227
0	0.5528780227
xx  1	0.5849625007
xx  1	0.5849625007
0	0.5077675659
1	0.5077675659
0	0.398488153
1	0.398488153
0	0.2892087401
1	0.2892087401
0	0.1799293271
1	0.1799293271
0	0.0706499142
xx  1	0.0706499142
xx  1	0.0386294987
0	0.0386294987
1	0.1479089116
0	0.1479089116
1	0.2571883245
0	0.2571883245
1	0.3664677374
0	0.3664677374
1	0.4757471503
0	0.4757471503
1	0.5849625007
1	0.5849625007
0	63.1760141404