So, log3/2,(3/2**108) becomes (3/2) * [2 *2*3*3*3] and we have are groups right there. (3/2) * [3 * 36]. A group, in my definition, is a set of digits at our two rates, in which the Shannon condition is matched.
Each of the 3 groups of 36 will match wave quant groups, at the Fibonacci rate. The next set of 108 would be separated by missing wave quants.
The thing likely writes out the 3 by 3 quark matrix all by itself. So, I will find the Shannon matching wave quants that fit with these groups, or variations. But still, I think, the atom can only have 36 or 72, up to the electron, it needs one more complete Plank volume if it were, at one time, matched to the magnetic. Then we have to have separation between gravity and magnetic.
Plotting the codependent quantizers
Here I took the two rates, co-sorted, out to 198, and computed the Shannon difference [(iLog(i) - jLog(j)] between the digits. The i and j would be equal in this idealized bit system, and represent the digit position.
Each point, out to 198 represents a digit in the two 198 bit numbers, one at the mass rate and one at the light rate. I sorted them so they are evenly matched. In the process I lost about 20 wave quants from the most significant position which did not match any mass quant.
A value lower means more entropy and more separation, so the low spots mark group separation.
This covers the smallest volume of vacuum density, the Plank density. The low spots will become structure. The high spots are where the probability of group overlap is high. They are both below one and meet Shannon, but that is not quite the happy result, because we will have to lose light quants at intermediate groups, they do not just come off at the end.
I am still trying to figure this out.
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